2/5k^2-3/5k-1=0

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Solution for 2/5k^2-3/5k-1=0 equation: 


k in (-oo:+oo)

(2/5)*k^2-((3/5)*k)-1 = 0

(2/5)*k^2+(-3/5)*k-1 = 0

2/5*k^2-3/5*k-1 = 0

DELTA = (-3/5)^2-(-1*2/5*4)

DELTA = 49/25

DELTA > 0

k = ((49/25)^(1/2)+3/5)/(2/5*2) or k = (3/5-(49/25)^(1/2))/(2/5*2)

k = 5/2 or k = -1

k in { -1, 5/2 }

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